 
 
 
 
 
 
 
  
 
 Why :  Assume for a minute that all your reflections have the same 
F/ (F) =
(F) =  . 
Then, because for the
initial (uniform) map all Fourier coefficients are identically zero (with the exception of F000), the statistic
. 
Then, because for the
initial (uniform) map all Fourier coefficients are identically zero (with the exception of F000), the statistic
 is given by
 is given by
 =
 = 
 =
 = 
 =
 = 
 2 = N
2 = N 2
2
 during the calculation is
 during the calculation is 
 = N. If
 = N. If 
 < 1.0, ie
 < 1.0, ie 
![average[F/sig(F)]](img72.gif) < 1.0, 
the uniform map will satisfy the
 < 1.0, 
the uniform map will satisfy the  constraint and  GraphEnt will stop immediately. Just because  GraphEnt stops, does not necessarily mean 
that there is no signal in the data : for Gaussian
noise,
constraint and  GraphEnt will stop immediately. Just because  GraphEnt stops, does not necessarily mean 
that there is no signal in the data : for Gaussian
noise, 
 
  N is the expected value of the distribution
 N is the expected value of the distribution 
 
  N
 N
 . This means
that depending on the data, the target of the calculation could as well be significantly lower than the value aimed 
for by  GraphEnt. I think it is worth emphasising this with an example. 
The following figure compares the conventional (left) and
 GraphEnt (right) map at the section v = 1/2 of the 20-3Å anomalous Patterson function for horse heart myoglobin crystals
(dashed contour at the mean, and then every 0.5 rmsd of the whole map). The 
data were collected with CuK
. This means
that depending on the data, the target of the calculation could as well be significantly lower than the value aimed 
for by  GraphEnt. I think it is worth emphasising this with an example. 
The following figure compares the conventional (left) and
 GraphEnt (right) map at the section v = 1/2 of the 20-3Å anomalous Patterson function for horse heart myoglobin crystals
(dashed contour at the mean, and then every 0.5 rmsd of the whole map). The 
data were collected with CuK radiation and the anomalous signal comes from the iron atom of heme
(this is one of the examples distributed with  GraphEnt, file  Myoglobin_anom_Patt_no_outliers.in).
 radiation and the anomalous signal comes from the iron atom of heme
(this is one of the examples distributed with  GraphEnt, file  Myoglobin_anom_Patt_no_outliers.in). 
A normal run of  GraphEnt with the whole data set 
would immediately stop with the ``uniformity'' message. Even after rejecting all
reflections with 
F/ (F) < 0.5,  GraphEnt would still refuse to co-operate (for 615 reflections with
F/
(F) < 0.5,  GraphEnt would still refuse to co-operate (for 615 reflections with
F/ (F) > 0.5, the initial
(F) > 0.5, the initial  --for the uniform map-- was 502.8). The map shown 
above could only be produced after
explicitly setting the  TARGet
 --for the uniform map-- was 502.8). The map shown 
above could only be produced after
explicitly setting the  TARGet  -value to 100.0 (by editing the  MAXENT_AUTO.IN file). As you
see, it probably worth the effort20.
-value to 100.0 (by editing the  MAXENT_AUTO.IN file). As you
see, it probably worth the effort20.
 
 Getting around it :  Start  GraphEnt the usual way. When the program stops with the ``uniformity'' message, edit
the  MAXENT_AUTO.IN and add a line with a new  TARGet value (which should be less than the starting
 value reported by the program if the  VERBose flag is set on, see page
 value reported by the program if the  VERBose flag is set on, see page ![[*]](cross_ref_motif.gif) ). Depending
on the circumstances, you could also add a line with  LIMIt 0.5 to exclude reflections with 
F/
). Depending
on the circumstances, you could also add a line with  LIMIt 0.5 to exclude reflections with 
F/ (F) < 0.5
(this should reduce the amount of computation required for convergence).
(F) < 0.5
(this should reduce the amount of computation required for convergence).
 is the correct way around. To continue with the example, even if we take the 
expected value of
 is the correct way around. To continue with the example, even if we take the 
expected value of  to be
 to be 
 
  N - 3
 N - 3 = 509 (ie 3
 = 509 (ie 3 away from the mean), 
the uniform map is still consistent with
the data. The fact that there seems to be some signal in the data when we reduce the  TARGet, probably points the
way to over-estimated standard deviations.
 away from the mean), 
the uniform map is still consistent with
the data. The fact that there seems to be some signal in the data when we reduce the  TARGet, probably points the
way to over-estimated standard deviations.
 
 
 
 
 
 
